Question

-14x^6y^3-21x^4y^5+7x^5y^4 by 7x^2y^2

Answer 1

Answer:

$\frac{ - 14 {x}^{6} {y}^{3} - 21 {x}^{4} {y}^{5} + 7 {x}^{5} {y}^{4} }{7 {x}^{2} {y}^{2} } \\ = \frac{7 {x}^{2} {y}^{2}( - 2 {x}^{4} y - 3 {x}^{2} y {}^{3} + {x}^{3} y {}^{2} }{7 {x}^{2} {y}^{2} } \\ = xy( {x}^{2} y - 2 {x}^{3} - 3x {y}^{2} )$