15.
1+cos A+sin A
1+cos A-sin A
1+sin A
cos A
Answers
Answered by
1
Step-by-step explanation:
1+cosA+sinA/1+cosA-sinA
devide cosA in both numerator & denominator
=secA+1+tanA/secA+1-tanA
=(secA+tanA+1)(secA-tanA)/ (secA-tanA+1)(secA-tanA)
=sec²A-tan²A+secA-tanA/ (secA-tanA+1)(secA-tanA)
=1+secA-tanA/(secA-tanA+1)(secA-tanA)
=1/secA-tanA
=secA+tanA/sec²A-tan²A
=secA+tanA
=1/cosA+sinA/cosA
=1+sinA/cosA
Similar questions