Question

15÷√10+√20+√40-√5-√80

Answer 1

4.35 is the value of $(15 \div \sqrt{10})+\sqrt{20}+\sqrt{40}-\sqrt{5}-\sqrt{80}$

Given:

$(15 \div \sqrt{10})+\sqrt{20}+\sqrt{40}-\sqrt{5}-\sqrt{80}$

To find:

$(15 \div \sqrt{10})+\sqrt{20}+\sqrt{40}-\sqrt{5}-\sqrt{80}= ?$

Solution:

To find the solution of the above problem we are going to use the BODMAS rule,

The first thing that we are going to do is to write the equation properly

$(15 \div \sqrt{10})+\sqrt{20}+\sqrt{40}-\sqrt{5}-\sqrt{80}$

First converting into roots to find common factor

$\left(\frac{15}{\sqrt{10}}\right)+2 \sqrt{5}+2 \sqrt{10}-\sqrt{5}-4 \sqrt{5}$

Taking the root 5 common we get the value of  

$\left(\frac{15}{\sqrt{10}}\right)+2 \sqrt{10}-\sqrt{5}(3)$

Therefore, the value of the above question is  

$\left(\frac{15}{\sqrt{10}}\right)+2 \sqrt{10}-\sqrt{5} .(3)=4.35$

Hence, after solving the question we get the solution as 4.35.