Question

15. 12(2x - 3y)²- 16(3y - 2x)​

Answer 1

Answer:

12(2x-3y)^2-16(3y-2x)

=12(3y-2x)^2-16(3y-2x)

=4(3y-2x) [3(3y-2x)-4]

=4(3y-2x) (9y-6x-4)

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Answer 2

Step-by-step explanation:

$12( {2x - 3y)}^{2} + 16(2x - 3y)$

let (2x-3y) be a...

${12a}^{2} + 16a = 0 \\ 4a(3a + 4) = 0 \\ a = 0 \: \: or \: \: a = \frac{ - 4}{3}$

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