15÷(-3)(4-7-3)÷(3(5+(-3)×(-6)}])
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Given 15-(-3) (4-6-2) ÷3 {5+(-3) ×(-6)}
Applying BODMAS & Left to Right Rule
= 15-(-3) (4-6-2) ÷3 {5+18}
= 15-(-3) (4-6-2) ÷3 {23}
= 15-(-3)(-4) ÷3*23
= 15–12 ÷3*23
= 15–4*23
= 15–92
= -77
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