Math, asked by kamleshdangi9, 5 days ago

--- 15.30 B. Find the HCF using the prime factorisation method. L. 87. 108 2 120, 180​

Answers

Answered by dongle70
0

Step-by-step explanation:

HCF of 72, 108 and 180 is the largest possible number that divides 72, 108 and 180 exactly without any remainder. The factors of 72, 108 and 180 are (1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72), (1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108) and (1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180) respectively. There are 3 commonly used methods to find the HCF of 72, 108 and 180 - long division, Euclidean algorithm, and prime factorization.

What is HCF of 72, 108 and 180?

Answer: HCF of 72, 108 and 180 is 36.

Answered by rimpakuila999
0

Answer:

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Step-by-step explanation:

Step 1: Divide 108 (larger number) by 72 (smaller number).

Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (72) by the remainder (36). Repeat this process until the remainder = 0.

⇒ HCF(72, 108) = 36.

Step 3: Now to find the HCF of 36 and 180, we will perform a long division on 180 and 36.

Step 4: For remainder = 0, divisor = 36 ⇒ HCF(36, 180) = 36

Thus, HCF(72, 108, 180) = HCF(HCF(72, 108), 180) = 36.

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