Math, asked by rfatma031, 11 months ago

15/4 m wire needed for the electric connection . How many connections can be made with 105 m of this wire.​

Answers

Answered by jyotip1005
16

Answer:

HEY!!!

HERE IS THE ANSWER TO YOUR QUESTION

It is going to be solved by unitary method

No. of electric conections by 15/4m of wire = 1

Then, by 1m of wire = 1/(15/4)

                                 = 4/15

So, by 105m of wire = \frac{4}{15} * 105

                                 =  4*7

                                 =  28

Therefore, We can get 28 electric connections by wire of length 105m...

HOPE YOU FIND IT HELPFUL:)

Answered by Qwparis
0

The correct answer is 28 m.

Given: Wire needed for electric connection = \frac{15}{4} m.

To Find: Connections made with 105 m of this wire.​

Solution:

Wire needed for electric connection = \frac{15}{4} m.

So, connection made by 105 m wire = \frac{Total wire}{wire required for connection}

= \frac{105}{\frac{15}{4} }.

= 105*\frac{4}{15}

= 7*4

= 28m

Hence, connections made with 105 m of this wire is 28 m.

#SPJ2

Similar questions