(√15 - √5)², Simplify.
Answers
Answered by
1
HEY MATE....✌
HERE'S THE ANSWER
________
FROM FORMULA:-
( a-b)^2= a^2+ b^2-2ab
(√15 -√5)^2=(√15)^2+(√5)^2-2√15*√5
=15+5-2√15*√5
=20-2√75
=2(10-√75)....@ns
HERE'S THE ANSWER
________
FROM FORMULA:-
( a-b)^2= a^2+ b^2-2ab
(√15 -√5)^2=(√15)^2+(√5)^2-2√15*√5
=15+5-2√15*√5
=20-2√75
=2(10-√75)....@ns
swagg0:
hi
Answered by
2
Hi ,
*******************************************
We know the algebraic identity :
( a - b )² = a² - 2ab + b²
*******************************************
Here ,
a = √15 , b = √5
Now ,
( √15 - √5 )²
= (√15 )² - 2 × √15 × √5 + ( √5 )²
= 15 - 2√( 15 × 5 ) + 5
= 20 - 2√( 5 × 3 × 5 )
= 20 - 10√3
= 10( 2 - √3 )
I hope this helps you.
: )
*******************************************
We know the algebraic identity :
( a - b )² = a² - 2ab + b²
*******************************************
Here ,
a = √15 , b = √5
Now ,
( √15 - √5 )²
= (√15 )² - 2 × √15 × √5 + ( √5 )²
= 15 - 2√( 15 × 5 ) + 5
= 20 - 2√( 5 × 3 × 5 )
= 20 - 10√3
= 10( 2 - √3 )
I hope this helps you.
: )
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