15.712 bar , bar on one and two
Answers
Answered by
3
Heya !!!
15.712 ( bar on 12)
Let X = 15.71212
Then X = 15.71212 -------(1)
Multiply equation (1) by 10 we get,
10X => 157.1212 -------(2)
Again multiply equation (2) by 100 we get
1000X = 15712.1212 ----(3)
Subtract equation (2) from equation (3) we get,
1000X = 15712.1212
10 = 157.1212
------------------
990X = 15555
X = 15555/990
Hence,
15.712 ( bar on 712) is in the form of 15555/990 which is in the form of P/Q
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
15.712 ( bar on 12)
Let X = 15.71212
Then X = 15.71212 -------(1)
Multiply equation (1) by 10 we get,
10X => 157.1212 -------(2)
Again multiply equation (2) by 100 we get
1000X = 15712.1212 ----(3)
Subtract equation (2) from equation (3) we get,
1000X = 15712.1212
10 = 157.1212
------------------
990X = 15555
X = 15555/990
Hence,
15.712 ( bar on 712) is in the form of 15555/990 which is in the form of P/Q
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
RehanAhmadXLX:
:-)
Answered by
10
Heya !!!
Here is Your Answer
Given :
15.7121212....
Let x = 15.71212....
Multiply by 10....
10x = 157.121212.... (i)
Multiply again till you get same repeating block of digits ...
100x = 1571.21212....
1000x = 15712.121212.... (ii)
Now, Subtract (I) from (II), we get.
x = 15555/990
Hope It Helps
Here is Your Answer
Given :
15.7121212....
Let x = 15.71212....
Multiply by 10....
10x = 157.121212.... (i)
Multiply again till you get same repeating block of digits ...
100x = 1571.21212....
1000x = 15712.121212.... (ii)
Now, Subtract (I) from (II), we get.
x = 15555/990
Hope It Helps
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