Question

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ɢᴏᴏᴅ ᴇᴠᴇɴɪɴɢ......

✅ɢɪᴠᴇɴ ᴛʜᴀᴛ 15ᴄᴏᴛ ᴀ=8.
ᴛʜᴇɴ ғɪɴᴅ sᴇᴄ ᴀ ᴀɴᴅ sɪɴ ᴀ.

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#samaira.

Answer 1

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15cotA = 8

cot = 8/15

Actually here use Pythagoras theorem .

cot = b/p

H = √p² + b²

H = √8² + 15²

H = √64 + 225

H = √289 = 17

But, sinA = p/h = 15/17 ☺

secA = h/b = 17/8 ☺

Since , sinA = 15/17 and secA = 17/8

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$.$

Answer 2

15cotA=8
cotA=8/15
cot^2A=cosec^2A-1
(8/15)^2=cosec^2A-1
64/225+1=cosec^2A
289/225=cosec^2A
√289/225= cosecA
17/15=cosecA
sinA=1/cosecA
sinA=1/17/15
sinA=15/17

Sin^2A+cos^2A=1
(15/17)^2+cos^2A=1
cos^2A=1-(15/17)^2
cos^2A=289-225/289
cos^2A=64/289
cosA=8/17
secA=1/cosA
secA=1/8/17
secA=17/8