Question

15. A 0.1 kg steel ball falls from a height of 10 m on the
ground and rebounds to a height of 7 m. (i) Why
does it not rebound to its original height? (ii) If the
dissipated energy remains in the ball in the form of
heat, then by how much will the temperature of the
ball be raised?​

Answer 1

Answer:

(i) This is known as Elastic collision when the

ball collided iite lost in the e qrovirdl;ome eupj was ball oud Tle deformation of ball and Outdoor. und.

(ii) ngh ms [ 72 =) ")

gh = S [ T2 - TI )

57,9.8. Elon- 7:)

gh gh 9.8x 3 29.4 J

8) = 110 cal

I cal = 4.2 J

(t う1/0 cal 462

CT'2;- TO]= 29.y こ

462

2 ニ 0.064 °C

ü

- + 10