Math, asked by sammy1298, 1 year ago

15/a+2/b = 17 , 1/a+1/b=36/5 find a+b​

Answers

Answered by letshelpothers9
3

Step-by-step explanation:

Substituition method solve

15/x + 2/y = 17 , 1/x + 1/y = 36/5

lets take a and b = x and y

15/ x + 2/y = 17 , 1/x + 1/y = 36/5

Solution:

 15/ x + 2/y = 17

 1/x + 1/y = 36/5

Let 1/x = a and 1/y = b

      15 a + 2 b = 17   -------- (1)

        a+b = 36/5

      5(a+b)=36

     5 a + 5 b = 36 -------- (2)

There are two unknowns in the given equations. By solving these equations we have to find the values of a and b.

For that let us consider the coefficients of x and y in both equation.

In the first equation we have + 15a and in the second equation also we have + 5a and the symbols are  same so we have to subtract them for eliminating the variable a.

                  15 a + 2 b = 17

(2) x 3 => 15 a + 15 b = 108

                 (-)   (-)       (-)     

                 ----------------

                      -13 b = -91

                           b = 91/13         

                            b = 7

now we have to apply the value of b in either given equations to get the value of another variable x

Substitute b = 7 in the first equation

        15 a + 2(7) = 17

        15 a + 14 = 17

        15 a = 17 – 14

        15a = 3

          a = 3/15  

           a = 1/5

Solution

   x = 5

   y = 1/7

verification:

15/ x + 2/y = 17

15/5 + 2/7 = 17

 3 + [2/(1/7)] = 17

 3 + 14  = 17

 17 = 17       

Answered by anuj2358
5

Step-by-step explanation:

15/ x + 2/y = 17

1/x + 1/y = 36/5

Let 1/x = a and 1/y = b

15 a + 2 b = 17 -------- (1)

a+b = 36/5

5(a+b)=36

5 a + 5 b = 36 -------- (2)

There are two unknowns in the given equations. By solving these equations we have to find the values of a and b. For that let us consider the coefficients of x and y in both equation. In the first equation we have + 15a and in the second equation also we have + 5a and the symbols are same so we have to subtract them for eliminating the variable a.

15 a + 2 b = 17

(2) x 3 => 15 a + 15 b = 108

(-) (-) (-)

----------------

-13 b = -91

b = 91/13

b = 7

now we have to apply the value of b in either given equations to get the value of another variable x

Substitute b = 7 in the first equation

15 a + 2(7) = 17

15 a + 14 = 17

15 a = 17 – 14

15a = 3

a = 3/15

a = 1/5

Solution

x = 5

y = 1/7

verification:

15/ x + 2/y = 17

15/5 + 2/7 = 17

3 + [2/(1/7)] = 17

3 + 14 = 17

17 = 17


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