Question

15. A bag containes 3 red balls and 4 white balls, One ball is drawn at random from the bag. Find the probability that the
ball drawn is a
1. White ball
2 .Blue ball
​

Answer 1

✧ Correct question :

A bag containes 3 red balls and 4 white balls, One ball is drawn at random from the bag. Find the probability that the ball drawn is a

1. White ball

2. Red ball

✧ Given :

• A bag containes 3 red balls and 4 white balls.

✧ To Find :

• Find the probability that the ball drawn is a :-

• 1. White ball
• 2. Red ball

✧ Solution :

We have :

White balls = 4

Red balls = 3

So, Total Balls = 4 + 3 = 7 balls

• We know that,

${ \underline{ \boxed{ \pink{ \sf{P(E) = \frac{ Number \: of \: favourable \: outcomes}{ Total\: Number \: of \: favourable \: outcomes}}} }}}$

1. White ball ?

➠ Favourable outcomes = 4

➠ Total outcomes = 7

$➠ \: { \sf{P(white \: balls) = \frac{4}{7} }}$

$➠ \: { \sf{Probability \: of \: white \: balls \: is \: { \boxed{ \blue{\frac{4}{7} }}}}}$

2. Red balls ?

➠ Favourable outcomes = 3

➠ Total outcomes = 7

$➠ \: { \sf{P(red \: balls) = \frac{3}{7} }}$

$➠ \: { \sf{Probability \: of \: red \: balls \: is \: { \boxed{ \blue{\frac{3}{7} }}}}}$

_____________________

Answer 2

Correct Question :-

A bag contains 3 red balls and 4 white balls, One ball is drawn at random from the bag. Find the probability that the

1. White ball
2. Red ball

Given :-

• A bag contains 3 red balls and 4 balls.

To find :-

• Find the probability that the ball drawn is a :-

1. White ball
2. Red ball

Solution :-

★ Now we have,

1. White balls = 4
2. Red balls = 3

So,

Total Balls = 4 + 3 = 7 balls

$\large{\bf\red{★}}$ We know that,

$\:\bigstar\underline{\boxed{\bf{\green{P(E) = \frac{Number \: of \: favourable \: outcomes}{Total \: Number \: of \: favourable \: outcomes}}}}}$

1. White balls ?

:$\implies\bf$ Favourable outcomes = 4

:$\implies\bf$ Total outcomes = 7

:$\implies\bf$ P (White balls) = $\large{\sf\pink{ \frac{4}{7} }}$

:$\implies\bf$ Probability of white balls is $\large{\sf\green{\frac{4}{7} }}$

2. Red balls ?

:$\implies\bf$ Favourable outcomes = 3

:$\implies\bf$ Total outcomes = 7

:$\implies\bf$ P (Red balls) = $\large{\sf\green{\frac{3}{7} }}$

:$\implies\bf$ Probability of red balls is $\large{\sf\pink{\frac{3}{7}}}$

Hence,

• Probability of white balls is $\boxed{\sf{\frac{4}{7}}}$ $\large{\bf\green{✓}}$

• Probability of red balls is $\boxed{\sf{\frac{3}{7}}}$ $\large{\bf\green{✓}}$