Question

15. A ball of mass 1 kg is dropped from 20 m height on ground and it rebounds to height
5 m. Find magnitude of change in momentum during its collision with the ground.
(Take g = 10 m/s2)​

Answer 1

Answer:

for downward motion ;

Explanation:

u=0 m/s

a=10 m/s2

s=20 m

using v2- u2=2as

v= 20m/s

for upward motion;

v=0 m/s

a=10 m/s2

s=5 m using v2 – u2=2as

u= -10 m/s

I=mv – mu

I=20+10=30 kg m/s

Answer 2

Answer:

The change in momentum is 30 kgm/s