Question

15. A balloon is rising with uniform speed 6 ms-1. At a
height 3.2 m from the ground a stone is dropped
from the balloon. The time taken by the stone to
strike the ground is (g = 10 m/s2)
1) 0.4 s
(2) 0.8 S
(3) 0.6 S
(4) 1.6 s​

Answer 1

Answer:

(s=ut +1/2at^2)  second equation of motion    s=3.2 accl.=10m/sec u=6m/sec

 

=-3.2=6t+1/2(-10)t^2

 

t=0.8 seconds

Explanation:

Answer 2

Answer:

1.6 seconds.

Explanation:

From the question we get that the height from which the stone is dropped is 3.2 m and the speed of the balloon is 6 m/s. So, according to the equation s=ut +1/2at^2 we will be able to find the time taken by the stone to strike the ground.

Hence, s=ut +1/2at^2, on substituting the values we will get that the height s is given in the question as 3.2m and the acceleration =10 and u=6m/sec. So,  3.2=-6t+1/2(10)t^2  which will be a quadratic equation 5t^2 - 6t - 3.2=0 which on solving we will get the time taken as 1.6 seconds.