Question

15
A body starts to slide over a horizontal surface
with an initial velocity of 0.5 m/s. Due to friction,
its velocity decreases at the rate 0.105 m/s. How
much time will it take for the body to stop?
[Ans. 4.8 s)​

Answer 1

Answer:

4.76

Explanation:

v = u+at

0 = .5 + (-.105) × t

t = (0 - .5)/(-.105)

t = 4.76

Answer 2

Answer:

hlo friend..the answer is..

Explanation:

u=0.5 m/s

a=0.05m/s sq.

v=0

by first equation of motion , we have

v=u+at

0=0.5 -0.05t

0 -0.5=0.05 t

-0.5=0.05t

0.5÷ 0.05=t

50/5=t

10 s =t

hope it will help u..