15. A bullet is fired horizontally on a vertical mud wall
after moving x distance in mud wall speed of bulle
becomes th of the initial speed. If bullet comes
to rest after travelling a further distance y, then y
is equal to
(1) *
(2) 5*
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Answer:
y = 9x/7
Explanation:
A bullet is fired horizontal on a vertical mud wall, after moving x distance in mud wall speed of bullet becomes 3/4th of the initial speed. if bullet comes rest after traveling a further distance y, then y is equal to
Using v² - u² = 2as
let say initial Velocity = v
after x distance it become 3v/4
=> (3v/4)² - v² = 2ax
=> 9v² - 16v² = 32ax
=> a = -7v²/32x
Further Distance y is covered before rest
=> 0² - (3v/4)² = 2ay
=> -9v²/16 = 2(-7v²/32x) y
=> y = 9x/7
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