15. A car starts from rest and moves along the x-axis with constant acceleration
5 m s-2 for 8 seconds. If it then continues with constant velocity, what
distance will the car cover in 12 seconds since it started from the rest?
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Answered by
2
Answer:
Given Below
Explanation:
Here:
The distance travelled in first eight seconds =x
1
=0+
2
1
∗5∗8
2
=160 m
At this point the velocity v=u+at=0+5×8=40 ms
−1
Therefore, the distance covered in last four seconds, x
2
=40×4=160m
Thus, the total distance x=x
1
+x
2
=160+160=320m
Answer By
B.Sai Kumar Yadav
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