Question

15. A dentist uses a small mirror that gives a magnification of 4 when it is held 0.60 cm from a tooth the
radius of curvature of the mirror is

Tadi​

Answer 1

Explanation:

R = 2f

u = - 0.60

v =?

m = -v/u

4= v/0.60

24=v

Answer 2

1.6 cm and concave mirror.

Explanation:

The magnification is given as

$m=\frac{v}{u}$

Here u is the object distance and v is image distance.

as, u = 0.60 cm.

Therefore,

$4=\frac{-v}{0.6cm}$

$v=-4\times0.6cm$

v = -2.4 cm.

Now from mirror formula,

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

Object held in front of mirror, so

$\frac{1}{f}=- \frac{1}{2.4cm}+\frac{1}{0.60cm}$

The radius of curvature id given as

$R =\frac{2}{f} =\frac{1}{ \frac{1}{-2.4cm}+\frac{1}{0.60cm}}$

R = + 1.6 cm.

As the radius of curvature is positive value so mirror is concave.

#Learn More: Mirror formula.

https://brainly.in/question/15553954