Question

15) A dice is tossed once. Find the probability of getting (a) a number greater than 4 (b) an even number​

Answer 1

Explanation:

S= { 1,2,3,4,5,6}

n(S) = 6

let P(A) be the event of getting that the number is greater than 4.

A= { 5,6}

n(A) = 2

P(A) = n(A)/n(S) = 2/6 = 1/3 = 0.3

Let P(B) video of getting that the number is an even number

B= {2,4,6}

n(B)= 3

P(B) = n(B)/n(S) = 3/6 = 1/2 = 0.5