Question

15. (a) Find mean deviation about mean :
15, 17, 22, 27, 30, 29, 35​

Answer 1

Answer:

Here N=29 (odd)

Median =(

2

N+1

)

th

observation

i.e. M=(

2

29+1

)

th

observation

⇒M=15

th

observation

Since, 15 occurs in the cumulative frequency 21. The corresponding observation is 30.

Hence, M=30

Mean deviation about median =

∑f

i

∑f

i

∣x

i

−M∣

=

29

148

=5.1