Question

15. (a) Find y, if y = cot-1
( sin 2x
1-COS 2x​

Answer 1

Answer:

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Step-by-step explanation:

Answer

Open in answr app

Correct option is

A

(2/3)

1/2

We have,

y=cot

−1

⎩

⎪

⎨

⎪

⎧

(cos2x)

2

1

⎭

⎪

⎬

⎪

⎫

So,

y=cot

−1

(

cos2x

)

On differentiation with respect to x and we get,

dx

dy

=−

1+(

cos2x

)

2

1

dx

d

cos2x

dx

dy

=−

1+(

cos2x

)

2

1

2

cos2x

1

dx

d

cos2x

dx

dy

=−

1+(

cos2x

)

2

1

2

cos2x

1

2(−sin2x)

dx

dy

=

1+cos2x

1

cos2x

sin2x

At x=

6

π

dx

dy

=

1+cos

6

2π

1

cos

6

2π

sin2

6

π

dx

dy

=

1+cos

3

π

1

cos

3

π

sin

3

π

dx

dy

=

1+

2

1

1

2

1

2

3

dx

dy

=

2

3

1

2

1

2

3

dx

dy

=

3

2

2

3

×

2

dx

dy

=

3

2

dx

dy

=(

3

2

)

2

1

Hence, this is the answer