Question

15) A flag is mounted on a car moving due North with velocity of 20km/hr. Strong winds are blowing
due East with velocity of 20 km/hr. The flag will point in direction:-
(A) East
(B) North-East (C) South-East (D) South-West​ ...explain via diagram

Answer 1

use trigonometric function to calculate

Answer 2

Given:

A flag is attached tour card moving towards not with the velocity of 20 km/hr. Strong winds are blowing towards east with a velocity of 20 km/hr.

To find:

The direction in which the flag will point.

Calculation:

Let Velocity of car be v_(c) and Velocity of wind be _(w).

So, the net direction of the flag will be such that it points opposite to the velocity of the car and towards the the velocity of the wind.

Hence , the flag will point in the South-East direction.

Let the flag make an angle of $\theta$ with velocity vector of wind.

$\therefore \: \tan( \theta) = \dfrac{v_{c}}{v_{w}}$

$= > \: \tan( \theta) = \dfrac{20}{20}$

$= > \: \tan( \theta) = 1$

$\boxed{ = > \: \theta = 45 \degree}$

So, precise direction of flag is 45° South of East.