15. A force of 50N acts on a particle along a direction making an angle of 37° with vertical. Its vertical component be: (a) 10N (b) 3N (C) 4N (d) 40N
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Answer:
the answer is c.40N
Explanation:
using the formula
Fy = Fsin(theta)
Fy = 50 x sin(90-37)
Fy = 50 x sin( 53)
Fy = 39.9N = 40N
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