Question

15. A hammer of mass 300 g, moving at 40m/s, strikes a nail. The nail stops the
hammer in a very short time of 0.02 s. The force of the nail on the hammer is
(a) 600N
(b) 1200N
(c) 2000N
(d) 2500N​

Answer 1

Answer:

600N will be the answer....

Explanation:

Answer 2

Given:

• The mass of the hammer = 300g = 0.3 Kg

• The initial velocity = 40 m/s
• The final velocity = 0 m/s
• Time = 0.02 secs.

To Find:

• The force of the nail on the hammer.

Solution:

We know that,

F = ma → {equation 1}

a = (v-u)/t → {equation 2}

On substituting equation 2 in 1 we get,

⇒ F = m(v-u)/t → {equation 3}

Where "m" is the mass, "v" is the final velocity, "u" is the initial velocity, "t" is the time.

On substituting the values in equation 3 we get,

⇒ F = 0.3(0-40)/0.02 {subtracting the terms in bracket}

⇒ F = 0.3(40)/0.02 {multipyling the terms in numerator}

⇒ F = 12/0.02 = 600 N {dividing the terms}

∴ The force of the nail on the hammer = 600 N (option a)