Question

15. A jogger runs down a straight stretch of road with an average velocity of 4.00 m/s for 2.00 min. What is his final position, taking his initial position to be zero?​

Answer 1

500 under going to speed is right answer

Answer 2

Given:

velocity u  = 4 m/s

time t = 2 min

To find :

final position s =?

Step-to-step-explanation:

• A jogger runs down a straight road with a velocity of 4.00 m/s for 2.00 min.

        i.e. initial velocity u = 4m/s

        time t = 2 min = 2 × 60 = 120 sec

• Consider his initial position to be zero.

• For after reaching the final position, a man stops running.

        i.e. final velocity v = 0 m/s

• We have to find that his final position he reached after running 2 minutes.

• Suppose ' S ' be the final position of man.

• By the law of the kinematical equation,

S =  ut + $\displaystyle \frac{1}{2}$ a $t^2$

   = 4(120) + 0.5 (9.81)(120)(120)

   = 480 + 70632

   = 71112 m

S = 71.112 Km

Hence the final position of man will be 71.112 Km.