15. A lag of Wood of dimensions 2m×20 cm×10cm is cut into small blacks of
10 cm x5 cm x 4cm How many blocks
do we get ? What will be total
surfac
e area of all these blocks?
Answers
Hey mate !!Good evening
Here is your answer
Length of log = 2m = 200cm
Breadth of log = 20 cm
Height of log = 10 cm
Volume of log of wood = l× b × h
= 200 × 20 × 10
=40000 cm³
Length of small block of wood = 10 cm
Breadth of small block of wood = 5 cm
Height of small block of wood = 4cm
Volume of 1 small block of wood = l×b×h
=10×5×4
=200cm³
Let the number of smallblock formed be n
Volume of log of wood = total number of small blocks
Therefore,
40000 = n × 200
n= 40000/200
n= 200 blocks
therefore,
we can form 200 block from the log of wood of 2m×20cm×10cm
Total surface area of 1 small block
= 2( lb + bh +lh )
= 2( 10×5 + 5×4 + 10 ×4)
= 2( 110 )
= 220 cm ²
Therefore,
Total surface area of 200 blocks=200×220 = 44000cm²
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