15. A man raises a box of mass 50 kg to a height
of 2 m in 20 s, while another man raises the same
box to the same height in 50 s.
(a) Compare : (i) the work done, and (ii) the power
developed by them.
(b) Calculate : (i) the work done, and (ii) the power
developed by each man. Take g = 10 N kg-1.
Answers
Answered by
19
Answer:
Work done by both of them is same, but power developed by them is 50 Watt and 20 Watt respectively.
Explanation:
Work done by first man = mgh
= 50 * 10 * 2
= 1000 J
Work done 2nd man = mgh
= 50 * 10 * 2
= 1000 J
Power developed by 1st man = Work / Time
= 1000 / 20
= 50 Watt
Power developed by 2nd man = Work / Time
= 1000 / 50
= 20 Watt
∴ Work done by both of them is same, but power developed by them is 50 Watt and 20 Watt respectively.
Answered by
18
Answer:
work done by first man= mgh
=50*2*10 =1000 b(i)
work done by second man=mgh
=50*2*10 = 1000
required ratio =1st man work/2nd man work
=1:1 Ans.1
1st man power = (50*2*10)/20
=50 b(ii)
2nd man power = (50*2*10)/50
=20 b(ii)
Required ratio=50:20
=5:2 @(ii)
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