Chemistry, asked by mangalamB, 9 months ago

15. A parachutist after mailing out falls
150m without seeiction when parachute
oppens it decelerates at amis de beaches
ground with smis. At whath, he fell down​

Answers

Answered by WhitEDeviLll
1

Explanation:

Let The Height Be "s" m.

Distance Covered Without Parachute = 50m

Initial Velocity = 0

Acceleration = 9.8 m/sec^{2}

v^{2}= u^{2}+2as

v^{2}= 2 x 9.8 x 50 = 980

v^{2}= 980

v = \sqrt{980}= 14 x \sqrt{5} m/sec

Now Remaining Distance = s-50

Initial Velocity = 14 x \sqrt{5}m/sec

Acceleration = -2 m/sec^{2}

v^{2}= u^{2}+2as

3^{2} = 980-4(s-50)

9 = 980-4s+200

9 = 1180-4s

4s = 1171

s = 292.75 m

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       ¶ THANK YOU ¶

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