Question

15. A particle moves a distance x in time t according to equation x = (t + 5)^-1 . The acceleration
of particle is proportional to

(a) (velocity)^3/2 (b) (distance) ^-2 (C) (velocity)^2/3
​

Answer 1

Answer:

(velocity)^3/2

Step-by-step explanation:

distance x = (t + 5)^-1

velocity v =dx/dt = d{(t + 5)^-1}/dt = -(t + 5)^-2

acceleration a = dv/dt = d{-(t + 5)^-2}/dt = 2(t + 5)^-3 = 2x^2 = 2v^3/2

=> acceleration is proportional to (velocity)^3/2