15) A person goes to his office from his home daily at fixed speed. One day he decided to reduce his speed by 20%. as a result he neaches his office 16 minutes late. The actual time that he takes to reach office daily is.
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Actual time = 64 min
Explanation:
Let v ( in m/min) be the fixed speed and t (in min) be the corresponding actual time.
New speed = v - 0.2v = 0.8 v = 4v/5 m/s
New time = (t + 16) min
distance cocered in both cases are sme
vt = 4v/5 x (t+16)
5t = 4t + 64
t = 64 min.
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