Math, asked by mujeebtetra, 10 months ago


15. A person spent 564 in buying pens and
pencils if cost of each pen is 7 and each
pencil is 3 and if the total number of things,
bought was 108, how many of each type did he buy?​

Answers

Answered by Anonymous
16

let's x be there total no. of pens and y be the total no. of pencils

7x + 3y = 564.............eq 1

x + y = 108..................eq 2

solving eq 1 and eq 2 we get

7x + 3y = 564.............eq1 x 1

7x + 7y = 756.................eq2 x 7

_____________

-4y = - 192

y = 48

from equation 2 we get

x + 48= 108

x = 108 - 48

x = 60

therefore the person both 60 pens and 48 pencils

Answered by prajwalxoxo17
4

Answer:

let's x be there total no. of pens and y be the total no. of pencils

7x + 3y = 564.............eq 1

x + y = 108..................eq 2

solving eq 1 and eq 2 we get

7x + 3y = 564.............eq1 x 1

7x + 7y = 756.................eq2 x 7

_____________

-4y = - 192

y = 48

from equation 2 we get

x + 48= 108

x = 108 - 48

x = 60

therefore the person both 60 pens and 48 pencils

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