Question

15. A spring balance carrying mass 20kg in a lift registered 250N
a. 2.5ms 2 down
b. 2.5ms up
c. 3.5ms down
d. 3.5ms up
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Answer 1

Answer:

a. 2.5ms^2 down

Explanation:

weight = force applied on the object = mass × acceleration

Answer 2

Answer:

The correct answer for the given problem is found to be option (A) $2.5m/s^2$ down.

Explanation:

The spring balance registered a weight of 250 N and we know that the reading registered by the spring is the sum of the weight and the force experienced by the spring.

Taking gravitational acceleration as 10 $m/s^2$.

We know that the expression for calculating the force exerted is given by:

Force (reading of the balance) = $mg+ma$

Let the acceleration experienced by the object be $a$.

Now, we are given the force as 250N and the mass of the object as 20kg, substituting this, we get:

$250=a\times20+10\times 20$

Simplifying this, we get:

$250-200=a\times20$

$50=20a$

or we can say:

$a=\frac{50}{20}$

$a=2.5m/s^2$

The force experienced by the spring is in the downwards direction.

So, the correct option is option (A) $2.5m/s^2$down.