Question

15) A thin metal disc of surface area 500 cm² at 0 °C is heated to 40 °C. Find the increase in the surface area of the disc. (o=4 x 10-⁵°C-1)​

Answer 1

Answer:

ΔT=110.8

Explanation:

Initial area A=π(35)

2

=3846.5cm

2

Change in area on heating ΔA=14.5cm

2

α=1.7×10

−5

We know that area expansion coefficient is twice of linear expansion coefficient.

So β=2α=2×1.7×10

−5

=3.4×10

−5

So ΔA=AβΔt

14.5=3846.5×3.4×10

−5

×ΔT

ΔT=110.8