Question

15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time
a tower casts a shadow 28 m long. Find the height of the tower.
​

Answer 1

Answer:

42m

Step-by-step explanation:

let AB a Pole and DE be a tower . hence ,the height of the tower is 42 metres.

Answer 2

Step-by-step explanation:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90

∘

both 90

∘

as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,

DE

AB

=

EF

BC

⇒

DE

6

=

28

4

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

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