Question

15. A water tank was full of water. Due to a leakage at the bottom 16-5% of the tank was
emptied in 2 hours. If the capacity of the tank was 1000 litres, find how much
(i) water is left in the tank,
le tank,
(ii) water misued.​

Answer 1

Answer:

(i)890 litres

(i)110 litres

Answer 2

(i) The quantity of water left in tank is 835 liters .

(ii)  The quantity of misuse water is 165 liters

Step-by-step explanation:

Given as :

The capacity of the tank = 1000 liters

The %age of water leakage = 16.5 %

The time at which tank empty = 2 hours

According to question

(i) Let The quantity of water left in tank = L liters

∵ %age of water leakage = 16.5 %

So, quantity of water left in tank = Total capacity of tank - total capacity in tank ×  %age of water leakage

i.e                                            L = 1000 liters - 1000 liters × 16.5%

Or,                                          L = 1000 - 1000 × $\dfrac{16.5}{100}$

Or,                                          L =  1000 - 1000 × 0.165

Or,                                          L = 1000 - 165

∴                                             L = 835 liters

So, The quantity of water left in tank =  L = 835 liters

Hence, The quantity of water left in tank is 835 liters . Answer

(ii) The quantity of misuse water = Total quantity in tank before - quantity in tank left after leakage

i.e The quantity of misuse water = 1000 liters - 835 liters

∴   The quantity of misuse water = 165 liters     .

Hence, The quantity of misuse water is 165 liters  Answer