Question

15. AABC is isosceles with AB = AC = 6.5 cm and BC = 8 cm. The height AD from A to BC is 5 cm. Find the area of AABC. What will be the height from C to AB (i.e., CE) ? ​

Answer 1

Step-by-step explanation:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=

2

1

×base×height=

2

1

×BC×AD

=

2

1

×9×6=27 cm

2

Again, Area of triangle=

2

1

×base×height=

2

1

×AB×CE

⇒27=

2

1

×7.5×CE

⇒ CE=

7.5

27×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm.

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