Question

15. An election was contested by two candidates A and B. In all there were 25000 voters.
80% of the votes were polled. If A got 60% of the total votes polled, how many votes did
B get?

Answer 1

Answer:

the number of votes A got = 12,000 , the number of votes B got = 13,000

Step-by-step explanation:

Therefore the number of votes got by A= 60% of 80% of 25000

$=\frac{60}{100}(\frac{80}{100}*25,000) =\frac{60}{100}(\frac{80}{1}*250) =\frac{60}{100}(20,000)\\\\=\frac{60}{100}*20,000=\frac{60}{1}*200=60*200=12,000-ANS$

Therefore the number of votes A got = 12,000

Therefore the number of votes got by B = 25,000-12,000=13,000-ANS

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