Question

15.An electric bulb of resistance 200ohms draws a current of 1 ampere calculate the power of the bulb the
potential difference at its end and the energy in kWh consumed burning it for 5h.
Please give me correct answers for me​

Answer 1

HopE tHIs HElps you....

Answer 2

Answer:

Resistance of electric bulb,R = 200ohms

Current,I = 1A

then,

Power, P= I^2R

P= 1^2 * 200

P = 200 W

Now, P= V^2/R

P= v^2/R

v^2 = P*R

v^2 = 200*200

v^2 = 400

ΔV = 20V

E = P*t

E = 200* 5h

E = 1000Wh

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