15.An object of mass 1 kg travelling in a straight line with a velocity of 10 ms collides with and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Answers
Answer:
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Step-by-step explanation:
Given
m = 1kg,
u1=10ms−1
M=5 kg and
u2= 0ms−1
Find out
The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Solution
From conservation of momentum
Initial momentum = final momentum
mu1 + Mu2 = (m+M)v
1×10 + 5×0 = (1+5)v
10=6v
Hence, the velocity of both is v =5/3ms−1
Total momentum before is 10 kgms−1
From momentum conservation, total momentum after is 10kgms−1.
Answer:
m = 1kg,
u1=10ms−1
M=5 kg and
u2= 0ms−1
Find out
The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Solution
From conservation of momentum
Initial momentum = final momentum
mu1 + Mu2 = (m+M)v
1×10 + 5×0 = (1+5)v
10=6v
Hence, the velocity of both is v =5/3ms−1
Total momentum before is 10 kgms−1
From momentum conservation, total momentum after is 10kgms−1.
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