Question

15.An object of mass 1 kg travelling in a straight line with a velocity of 10 ms collides with and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.​??spam =10 answer report?​

Answer 1

Explanation:

Here, Mass of object, m1 = 1 kg

And, Velocity of object, v1 = 10 m s–1

So, Momentum of object = m1 × v1

= 1 × 10 kg m s–1

= 10 kg m s–1 ...(1)

Now, Mass of wooden block, m2 = 5 kg

And, Velocity of wooden block, v2 = 0 (It is stationary)

So, Momentum of wooden block = m2 × v2

= 5 × 0

= 0 kg m s–1 ...(2)

Total momentum = 10 + 0

before impact = 10 kg m s–1 ...(3)

Now, according to the law of conservation of momentum, the total momentum just after the impact will be the same as the total momentum just before the impact. This means that the total momentum just after the impact will also be 10 kg m s–1.

Now, Total momentum = 10 kg m s–1

Total mass of object = 1 kg + 5 kg

and wooden block = 6 kg

And Velocity of object = v m s–1 (Supposed)

and wooden block

So, 10 = 6 × v

And,v= 10/6

v = 1.67 m s–1

Thus, the velocity of the object and wooden block together is 1.67 metres per second