15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of local
length 18 cm. At what distance from the mirror should a screen be placed, so that
a sharp focussed image can be obtained? Find the size and the nature of the image.
201 What type of lens is this?
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I = -14 cm
Explanation:
Given:
size of object, o=+7cm
distance of object ,u=−27cm
focal length of concave mirror, f=−18cm
let us take size of image=I
so, mirror formula is = 1/v + 1/4 = 1/f
so, putting values of u and v,
1/v = 1/+8 - 1/-27
1/v = 1/-54
v=−54cm
so, image is formed on object side only.
magnification,
m=-v/4 = I/o
m= -54/-27 = I/7
I=−14cm
Hence, The image is double in size to that of object & It's Nature is real, inverted and magnified image.
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