Question

15. An object travels with a constant velocity of 20m/s for 5sec.Then it accelerates with 5m/s² for 2 sec

and again retards with 2m/sec² and finally comes to rest. Calculate the total distance travelled by the

object.​

Answer 1

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The velocity acquired by the particle at t = __ is ___(v=u+at). It takes further __ s to comes to rest under retardation of __. Distance travelled in the interval _____ (use s=ut+12at2) and the distance travelled in the interval __to ___ (use v2=u2+2as). Let the particle start from x = 0. The final position of particle is x = ____