Question

15 and 21 lcm and hcf of following integers by applying the prime factorisation method.

$12 = 2 \times 2 \times 3 = 2 { }^{2} \times 3 \\ 15 = 3 \times 5 \\ 21 = 3 \times 7 \\ hcf = 3 \\ lcm = 2 {}^{2} \times 3 \times 5 \times 7 = 420$
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Answer 1

Answer:

HCf of 15=3*5*1

hcf of 21=3*7*1

HCF =15=3*5*1

HCF=21=3*7*1

HCF=1*3=3

here the proof

Answer 2

Answer:

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