15% aqueous solution (w/w) of glucose which have density 1.2 g/cc. calculate molarity & molality hints - 15%. aq. sol. of glucose (w/w) means 15 g glucose is
dissolved in 100g solution
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Answer:
Molality = mass of solvent in kgno of moles of solute
Molar mass of glucose = 180g
Mass of glucose =10
No of moles of glucose =18010=0.0556mol
the solution of glucose in water which is 10% w/W means 10 g of glucose in 100 g of solution
Mass of solvenyt=100-10=90 g =0.090 kg
Molality = 0.0900.556=0.617m
Hence, the correct option is B
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