Question

15。
|
B-JR-FA how can I rationalise this number ​

Answer 1

Step-by-step explanation:

1/(√5-√2)-√7×(√5-√2)+√7/(√5-√2)+√7

=(√5-√2)+√7/(√5-√2)²-(√7)²

=(√5-√2)+√7/[(√5)²-2×√5×√2+(√2)²]-(√7)²

=(√5-√2)+√7/[5-2√6+2]-7

=(√5-√2)+√7/5-2√6+2-7

=(√5-√2)+√7/ 7-2√6-7

=(√5-√2)+√7/2√6

=(√5-√2)+√7/ 2√6×√6/√6

=√30-√12+√42/2×(√6)²

=√30-2√3+√42/2×6

=√30-2√3+√42/12

=√30-√3+√42/6