15 bulbs of 60 watt works for 6 hour daily and a refrigerator of 360watt works for 5 hours daily .Find the energy required daily if per unit cost Rs.3.
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Given,
P1=60watt
=60/1000 KW
=3/50 KW
P2=360watt
=360/1000
=9/25
T1=6hours
T2=5hours
For P1,
Energy(E)=power(P)×Time(T)
E=3/50×6
E=0.36 KWH
For P2,
E2=P2×T2
E2=9/25×5
E2=1.8 KWH
Total energy,
E1+E2=0.36+1.8=2.16 KWH
per unit cost = 3rs
So,
2.16×3=6.48rs
cost will be 6.48 rs
P1=60watt
=60/1000 KW
=3/50 KW
P2=360watt
=360/1000
=9/25
T1=6hours
T2=5hours
For P1,
Energy(E)=power(P)×Time(T)
E=3/50×6
E=0.36 KWH
For P2,
E2=P2×T2
E2=9/25×5
E2=1.8 KWH
Total energy,
E1+E2=0.36+1.8=2.16 KWH
per unit cost = 3rs
So,
2.16×3=6.48rs
cost will be 6.48 rs
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