15. Calculate (i) mass of 5.8 mol of N2O (ii) Number of moles of 8 g of O2 (iii) Number of moles of 11.2 lit of CO2 gas at STP
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1. gram atomic mass of N20 = 28+16 = 44. 1mole contains 44 g. so, 5.8 moles contain = (44×5.8)g = 255.2g
2. 32g = 1mole. then 8g = 8÷32 = 0.25 moles.
3. 11.2L is half of 22.4L hence it contains 0.5 mol of gas.
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