Question

15 cot A =8 find sin A and Sec C

Answer 1

Answer:

$15 \cot(a) = 8 \\ \cot(a) = \frac{8}{15} = \frac{base}{perpendicular} \\ base = 8 \\ pependicular = 15 \\ hypotnuse = 17 \\ \sin(a) = \frac{p}{h} = \frac{15}{17} \\ \sec(a) = \frac{h}{b} = \frac{17}{8} .$

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Answer 2

Answer:

Sin A = 15/17,Sec C = 17/8

Step-by-step explanation:

15 cot A =8

cot A= 8/15

cot A = 8/15  = base/height

Let height be 15x and base be 8x

By Pythagoras Theorem,

(15x)^2 + (8x)^2 = hypotenuse^2

(225 + 64)x^2  = hypotenuse^2

289x^2 = hypotenuse^2

17x  = hypotenuse

Now,

sin A = height/hypotenuse

Sin A = 15/17

sec C = hypotenuse/base

Sec C = 17/8

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