15 cot A=8,find sinA and secA
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hope it helps..............
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hey mate here is your answer....
Step-by-step explanation:
▶️ Let ABC be a right angled triangle, right angled at B.
➡️ We know that cotA = AB / BC = 8 / 15
➡️ Let AB be 8k and BC be 15k, where k is the positive real number.
▶️ By Pythagoras theorem we get
- AC² = AB² + BC²
- AC² = (8k)² + (15k)²
- AC² = 64k² + 225k²
- AC² = 289k²
- AC = 17k
▶️ sinA = BC / AC = 15k / 17k = 15 / 17
▶️ secA = AC / AB = 17k / 8k = 17 / 8
Hope it helps!☺️
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